Pressure inside two soap bubbles are $1.02 \,atm$ and $1.05 \,atm$ respectively. The ratio of their surface area is .........

What is the excess pressure inside a bubble of soap solution of radius $5.00 \;mm$, given that the surface tension of soap solution at the temperature ($20\,^{\circ} C$) is $2.50 \times 10^{-2}\; N m ^{-1}$ ? If an air bubble of the same dimension were formed at depth of $40.0 \;cm$ inside a container containing the soap solution (of relative density $1.20$), what would be the pressure inside the bubble? ($1$ atmospheric pressure is $1.01 \times 10^{5} \;Pa$ ).

Two long parallel glass plates has water between them. Contact angle between glass and water is zero. If separation between the plates is $'d'$ ( $d$ is small). Surface tension of water is $'T'$ . Atmospheric pressure = $P_0$ . Then pressure inside water just below the air water interface is 

A soap bubble of radius $3\, {cm}$ is formed inside the another soap bubble of radius $6\, {cm}$. The radius of an equivalent soap bubble which has the same excess pressure as inside the smaller bubble with respect to the atmospheric pressure is .......... ${cm}$ 

If the radius of a soap bubble is four times that of another, then the ratio of their excess pressures will be

The adjoining diagram shows three soap bubbles $A, B$ and $C$ prepared by blowing the capillary tube fitted with stop cocks, $S_1$, $S_2$ and $S_3$. With stop cock $S$ closed and stop cocks $S_1$, $S_2$ and $S_3$ opened