Probability that a student will succeed in IIT entrance test is 0.2 and that he will succeed in Roor

English

Gujarati

Hindi

14.Probability

hard

Probability that a student will succeed in $IIT$ entrance test is $0.2$ and that he will succeed in Roorkee entrance test is $0.5$. If the probability that he will be successful at both the places is $0.3$, then the probability that he does not succeed at both the places is

$0.4$

$0.3$

$0.2$

$0.6$

Solution

(d) Let $A$ denotes the event that the student is selected in $IIT$ entrance test and $B$ denotes the event that he is selected in Roorkee entrance test. Then

$P(A) = 0.2,\,\,P(B) = 0.5$ and $P(A \cap B) = 0.3.$

Required probability $ = P(\overline A \cap \overline B) = 1 – P(A \cup B)$

$ = 1 – (P(A) + P(B) – P(A \cap B))$

$ = 1 – (0.2 + 0.5 – 0.3) = 0.6$.

Standard 11

Mathematics

$A$ and $B$ are events such that $P(A)=0.42$, $P(B)=0.48$ and $P(A$ and $B)=0.16 .$ Determine $P (A$ or $B).$

easy

Urn $A$ contains $6$ red and $4$ black balls and urn $B$ contains $4$ red and $6$ black balls. One ball is drawn at random from urn $A$ and placed in urn $B$. Then one ball is drawn at random from urn $B$ and placed in urn $A$. If one ball is now drawn at random from urn $A$, the probability that it is found to be red, is

hard

(IIT-1988)

One bag contains $5$ white and $4$ black balls. Another bag contains $7$ white and $9$ black balls. A ball is transferred from the first bag to the second and then a ball is drawn from second. The probability that the ball is white, is

hard

Let $A$ and $B$ be independent events with $P(A)=0.3$ and $P(B)=0.4$. Find $P(A \cup B)$

easy

For an event, odds against is $6 : 5$. The probability that event does not occur, is

easy

Probability that a student will succeed in $IIT$ entrance test is $0.2$ and that he will succeed in Roorkee entrance test is $0.5$. If the probability that he will be successful at both the places is $0.3$, then the probability that he does not succeed at both the places is

Solution

Similar Questions

$A$ and $B$ are events such that $P(A)=0.42$, $P(B)=0.48$ and $P(A$ and $B)=0.16 .$ Determine $P (A$ or $B).$

One bag contains $5$ white and $4$ black balls. Another bag contains $7$ white and $9$ black balls. A ball is transferred from the first bag to the second and then a ball is drawn from second. The probability that the ball is white, is

Let $A$ and $B$ be independent events with $P(A)=0.3$ and $P(B)=0.4$. Find $P(A \cup B)$

For an event, odds against is $6 : 5$. The probability that event does not occur, is

Start a Free Trial Now