Let $A$ and $B$ be independent events with $P(A)=0.3$ and $P(B)=0.4$. Find $P(A \cup B)$
Let $A$ and $B$ be independent events with $P(A)=0.3$ and $P(B)=0.4$. Find $P(A \cup B)$
It is known that, $P(A \cup B)=P(A)+P(B)-P(A \cap B)$
$\Rightarrow $ $P(A \cup B)=0.3+0.4-0.12=0.58$
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Fill in the blanks in following table :
$P(A)$
$P(B)$
$P(A \cap B)$
$P (A \cup B)$
$0.5$
$0.35$
.........
$0.7$
Fill in the blanks in following table :
| $P(A)$ | $P(B)$ | $P(A \cap B)$ | $P (A \cup B)$ |
| $0.5$ | $0.35$ | ......... | $0.7$ |