Projection of vector $\vec A$ on $\vec B$ is
$\vec A.\vec B$
$\vec A.\hat B$
$\vec B \times \vec A$
$\hat B.\hat A$
For three vectors $\vec{A}=(-x \hat{i}-6 \hat{j}-2 \hat{k})$, $\vec{B}=(-\hat{i}+4 \hat{j}+3 \hat{k})$ and $\vec{C}=(-8 \hat{i}-\hat{j}+3 \hat{k})$, if $\overrightarrow{\mathrm{A}} \cdot(\overrightarrow{\mathrm{B}} \times \overrightarrow{\mathrm{C}})=0$, them value of $\mathrm{x}$ is. . . . . ..
Which of the following is not true ? If $\overrightarrow A = 3\hat i + 4\hat j$ and $\overrightarrow B = 6\hat i + 8\hat j$ where $ A$ and $B$ are the magnitudes of $\overrightarrow A $ and $\overrightarrow B $
colum $I$ | colum $II$ |
$(A)$ $A \cdot B =| A \times B |$ | $(p)$ $\theta=90^{\circ}$ |
$(B)$ $A \cdot B = B ^2$ | $(q)$ $\theta=0^{\circ}$ or $180^{\circ}$ |
$(C)$ $|A+B|=|A-B|$ | $(r)$ $A=B$ |
$(D)$ $|A \times B|=A B$ | $(s)$ None |
The area of the parallelogram whose sides are represented by the vectors $\hat j + 3\hat k$ and $\hat i + 2\hat j - \hat k$ is
The position vectors of points $A, B, C$ and $D$ are $A = 3\hat i + 4\hat j + 5\hat k,\,\,B = 4\hat i + 5\hat j + 6\hat k,\,\,C = 7\hat i + 9\hat j + 3\hat k$ and $D = 4\hat i + 6\hat j$ then the displacement vectors $AB$ and $CD $ are