Gujarati
Hindi
5.Work, Energy, Power and Collision
normal

Pulley and spring are massless and the friction is absent everwhere. $5\,kg$ block is released from rest. The speed of $5\,kg$ block when $2\,kg$ block leaves the contact with ground is (take force constant of the spring $K = 40\,N/m$ and $g = 10\,m/s^2$ )

A

$\sqrt 2\,m/s$

B

$2\sqrt 2\,m/s$

C

$2\,m/s$

D

$4\sqrt 2\,m/s$

Solution

$\mathrm{kx}=2 \mathrm{g} \Rightarrow \mathrm{x}=0.5$

By $COME$ $5 \times 10 \times 0.5=\frac{1}{2} \times 5 v^{2}+\frac{1}{2} \times 40 \times(5)^{2}$

$25=\frac{5}{2} v^{2}+5$

$v^{2}=8$

$\mathrm{v}=2 \sqrt{2} \mathrm{m} / \mathrm{s}$

Standard 11
Physics

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