Quantity Z varies with x and y , according to given equation Z = x^2y - xy^2 , where x = 3.0 p

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1.Units, Dimensions and Measurement

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Quantity $Z$ varies with $x$ and $y$ , according to given equation $Z = x^2y - xy^2$ , where $x = 3.0 \pm 0.1$ and $y = 2.0 \pm 0.1$ . The value of $Z$ is

A

$6 \pm 1.1$

B

$6 \pm 1.4$

C

$6 \pm 1$

D

$6 \pm 0.1$

Solution

$\delta \mathrm{Z}=\left|2 \mathrm{xy}-\mathrm{xy}^{2}\right| \delta \mathrm{x}+\left|\mathrm{x}^{2}-2 \mathrm{xy}\right| \delta \mathrm{y}=1.1$

$\mathrm{Z}=\mathrm{x}^{2} \mathrm{y}-\mathrm{x} \mathrm{y}^{2}=6$

So $Z=6 \pm 1$

Standard 11

Physics

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