Find the relative error in $Z,$ if $Z=\frac{A^{4} B^{1 / 3}}{ C D^{3 / 2}}$
Find the relative error in $Z,$ if $Z=\frac{A^{4} B^{1 / 3}}{ C D^{3 / 2}}$
$\text {Answer The relative error in } Z \text { is } \Delta Z / Z=$
$4(\Delta A / A)+(1 / 3)(\Delta B / B)+(\Delta C / C)+(3 / 2)(\Delta D / D)$
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- [NEET 2019]
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