The relative error in the determination of the surface area of a sphere is $\alpha $. Then the relative error in the determination of its volume is
$\frac{2}{3}\alpha $
$\frac{5}{2}\alpha $
$\frac{3}{2}\alpha $
$\alpha $
Two resistors of resistances $R_{1}=100 \pm 3$ $ohm$ and $R_{2}=200 \pm 4$ $ohm$ are connected $(a)$ in series, $(b)$ in parallel. Find the equivalent resistance of the $(a)$ series combination, $(b)$ parallel combination. Use for $(a)$ the relation $R=R_{1}+R_{2}$ and for $(b)$ $\frac{1}{R^{\prime}}=\frac{1}{R_{1}}+\frac{1}{R_{2}}$ and $\frac{\Delta R^{\prime}}{R^{\prime 2}}=\frac{\Delta R_{1}}{R_{1}^{2}}+\frac{\Delta R_{2}}{R_{2}^{2}}$
A physical quantity $P$ is given by $P= \frac{{{A^3}{B^{\frac{1}{2}}}}}{{{C^{ - 4}}{D^{\frac{3}{2}}}}}$. The quantity which brings in the maximum percentage error in $P$ is
Error in volume of a sphere is $6\%$. Error in its radius will be .......... $\%$
The most accurate reading of the length of a $6.28 \,cm$ long fibre is ............... $cm$
The length of a cylinder is measured with a metre rod having least count $0.1 \;cm$. Its diameter is measured with vernier calipers having least count $0.01\; cm$. If the length and diameter of the cylinder are $5.0\; cm$ and $2.00\; cm$, respectively, then the percentage error in the calculated value of volume will be