Radioactive element decays to form a stable nuclide, then rate of decay of reactant is

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13.Nuclei

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Radioactive element decays to form a stable nuclide, then the rate of decay of reactant is

A

B

C

D

(AIIMS-2012)

Solution

No. of nuclide at time t is given by

$\mathrm{N}=\mathrm{N}_{0} \mathrm{e}^{-\lambda \mathrm{t}}$

Where $\mathrm{N}_{0}=$ initial nuclide

thus this equation is equivalent to $y = a{e^{ – kx}}$

Thus correct graph is

Standard 12

Physics

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