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13.Nuclei
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The activity of a radioactive sample is $1.6\, curie$ and its half-life is $2.5 \,days$. Its activity after $10\, days$ will be .......... $curie$
A
$0.8 $
B
$0.4$
C
$0.1$
D
$0.16$
Solution
(c) Number of half lives $n = \frac{{10}}{{2.5}} = 4$
==> $\frac{A}{{{A_0}}} = \frac{N}{{{N_0}}} = {\left( {\frac{1}{2}} \right)^n} $
$\Rightarrow A = 1.6 \times {\left( {\frac{1}{2}} \right)^4} = 0.1\;curie$
Standard 12
Physics
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