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13.Nuclei
medium
Radius of the second Bohr obit of singly ionised helium atom is ......... $ \mathring A $
A$0.53$
B$1.06$
C$0.265 $
D$0.132$
Solution
Radius of nth Bohr orbit $r _{ n }=\frac{0.529 n ^2}{ Z } A ^{\circ}$
For ionised Helium atom $Z =2$
Second Bohr orbit $n =2$
$\Rightarrow r _2=\frac{0.529 \times 2^2}{2}=1.06\, \mathring A$
For ionised Helium atom $Z =2$
Second Bohr orbit $n =2$
$\Rightarrow r _2=\frac{0.529 \times 2^2}{2}=1.06\, \mathring A$
Standard 12
Physics
