Show that the coefficient of area expansion, $(\Delta A / A) / \Delta T,$ of a rectangular sheet of the solid is twice its Iinear expansivity, $\alpha_{1}$
Consider a rectangular sheet of the solid material of length $a$ and breadth $b$ . When the temperature increases by $\Delta T, a$ increases by $\Delta a=\alpha_{1} a\Delta T$ and $b$ increases by $\Delta b$ $=\alpha_{1} b \Delta T .$ the increase in area
$\Delta A =\Delta A_{1}+\Delta A_{2}+\Delta A_{3}$
$\Delta A =a \Delta b+b \Delta a+(\Delta a) \quad(\Delta b)$
$=a \alpha_{1} b \Delta T+b \alpha_{1} a \Delta T+\left(\alpha_{1}\right)^{2} a b(\Delta T)^{2}$
$ = {\alpha _1}ab\Delta T\left( {2 + {\alpha _1}\Delta T} \right) = {\alpha _1}A\Delta T(2 + {\alpha _1}\Delta T)$
since $\alpha_{1}=10^{-5} K ^{-1},$ from Table $11.1,$ the product $\alpha_{1} \Delta T$ for fractional temperature is small in comparision with 2 and may be neglected. Hence
$\left(\frac{\Delta A}{A}\right) \frac{1}{\Delta T} \simeq 2 \alpha_{l}$
Two rods $A$ and $B$ of identical dimensions are at temperature $30\,^oC$. If a heated upto $180\,^oC$ and $B$ upto $T\,^oC$, then the new lengths are the same. If the ratio of the coefficients of linear expansion of $A$ and $B$ is $4:3$, then the value of $T$ is........$^oC$
A pendulum clock (fitted with a small heavy bob that is connected with a metal rod) is $5\, seconds$ fast each day at a temperature of $15\,^oC$ and $10\,seconds$ slow at a temperature of $30\,^oC$. The temperature at which it is designed to give correct time, is ........ $^oC$
If a cylinder of diameter $1.0\, cm$ at $30°C$ is to be solid into a hole of diameter $0.9997\, cm$ in a steel plate at the same temperature, then minimum required rise in the temperature of the plate is ........ $^oC$ (Coefficient of linear expansion of steel $ = 12 \times {10^{ - 6}}°C^{-1}$)
A metallic bar of Young's modulus, $0.5 \times 10^{11} \mathrm{~N} \mathrm{~m}^{-2}$ and coefficient of linear thermal expansion $10^{-5}{ }^{\circ} \mathrm{C}^{-1}$, length $1 \mathrm{~m}$ and area of cross-section $10^{-3} \mathrm{~m}^2$ is heated from $0^{\circ} \mathrm{C}$ to $100^{\circ} \mathrm{C}$ without expansion or bending. The compressive force developed in it is :
An aluminium sphere of $20 \;cm$ diameter is heated from $0^{\circ} C$ to $100^{\circ} C$. Its volume changes by (given that coefficient of linear expansion for aluminium $\alpha_{A l}=23 \times 10^{-6}\;/{^o}C$