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6-2.Equilibrium-II (Ionic Equilibrium)
medium
Solubility of $Th_3(PO_4)_4$ $(M_w = m)$ is $w\,g/100\,ml$ at $25\,^oC$ . $K_{SP}$ is
A
$6.912\, \times \,{10^{10}}\,{\left( {\frac{w}{m}} \right)^7}$
B
$6.912\, \times \,{10^{3}}\,{\left( {\frac{w}{m}} \right)^7}$
C
$1.08\, \times \,{10^{7}}\,{\left( {\frac{w}{m}} \right)^5}$
D
$10^2\, \times \,{\left( {\frac{w}{m}} \right)^2}$
Solution
$Th _3\left( PO _4\right)_4 \rightleftharpoons 3 Th ^{4+}+4 PO^{3-}$
$\quad\quad\quad\quad\quad\quad\quad3s\quad\quad\quad3s$
$K _{ sp }=3^3 \cdot 4^4 \cdot( s )^7$
$=6912 \times\left(\frac{10 \,w }{ m }\right)^7 \quad\left( s =\frac{10\, w }{ m } \,mol /\right.$ litre $)$
$=6.912 \times 10^{10} \times\left(\frac{ w }{ m }\right)^7$
Standard 11
Chemistry
