Standing waves are produced in a 10 m long stretched string. If string vibrates in 5 segments and wa

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14.Waves and Sound

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Standing waves are produced in a $10 \;m$ long stretched string. If the string vibrates in $5$ segments and the wave velocity is $20\; m/s$, the frequency is ... $Hz$

A

$2$

B

$4$

C

$5$

D

$10$

(AIIMS-1998) (AIPMT-1997)

Solution

(c) String vibrates in five segment so $\frac{5}{2}\lambda = l$

==> $\lambda = \frac{{2l}}{5}$

Hence $n = \frac{v}{\lambda } = 5 \times \frac{v}{{2l}}$$ = 5 \times \frac{{20}}{{2 \times 10}} = 5$$Hz$

Standard 11

Physics

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