Starting from rest a scooter acquires a velocity of 36, km h^{-1} in 10 ,s and then brakes are appli

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7. MOTION

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Starting from rest a scooter acquires a velocity of $36\, km h^{-1}$ in $10 \,s$ and then brakes are applied it takes $20\, s$ to stop. Calculate acceleration and distance travelled.

Option A

Option B

Option C

Option D

Solution

$u=36 km h ^{-1}=10 m s ^{-1}$

$u=0$

$t=10 s$

$\therefore \quad a=\frac{v-u}{t}$.

$=\frac{10}{10}=1 ms ^{-2}$

$S=u t+\frac{1}{2} a t^{2}$

$=0+\frac{1}{2} \times 1 \times 400$

$=200 \,m$,

Standard 9

Science

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