Starting from rest a scooter acquires a velocity of $36\, km h^{-1}$ in $10 \,s$ and then brakes are applied it takes $20\, s$ to stop. Calculate acceleration and distance travelled.
Starting from rest a scooter acquires a velocity of $36\, km h^{-1}$ in $10 \,s$ and then brakes are applied it takes $20\, s$ to stop. Calculate acceleration and distance travelled.
$u=36 km h ^{-1}=10 m s ^{-1}$
$u=0$
$t=10 s$
$\therefore \quad a=\frac{v-u}{t}$.
$=\frac{10}{10}=1 ms ^{-2}$
$S=u t+\frac{1}{2} a t^{2}$
$=0+\frac{1}{2} \times 1 \times 400$
$=200 \,m$,
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The following table show os the positon of three persons between $8.00\, am$ to $8.20\, am$.
Time
Position (in $km$)
Person $A$
Person $B$
Person $C$
$8.00 \,am$
$0$
$0$
$0$
$8.05 \,am$
$4$
$5$
$10$
$8.10\, am$
$13$
$10$
$19$
$8.15 \,am$
$20$
$15$
$24$
$8.20\, am$
$25$
$20$
$27$
$(i)$ Who is moving with constant speed ?
$(ii)$ Who has travelled maximum distance between $8.00\, am$ to $8.05\, am$ ?
$(iii)$ Calculate the average speed of person $'A^{\prime}$ in $k m h^{-1}$
The following table show os the positon of three persons between $8.00\, am$ to $8.20\, am$.
| Time | Position (in $km$) | ||
| Person $A$ | Person $B$ | Person $C$ | |
| $8.00 \,am$ | $0$ | $0$ | $0$ |
| $8.05 \,am$ | $4$ | $5$ | $10$ |
| $8.10\, am$ | $13$ | $10$ | $19$ |
| $8.15 \,am$ | $20$ | $15$ | $24$ |
| $8.20\, am$ | $25$ | $20$ | $27$ |
$(i)$ Who is moving with constant speed ?
$(ii)$ Who has travelled maximum distance between $8.00\, am$ to $8.05\, am$ ?
$(iii)$ Calculate the average speed of person $'A^{\prime}$ in $k m h^{-1}$