Gujarati
Hindi
Mathematical Reasoning
normal

Statement $-1$ : $ \sim \left( {p \leftrightarrow \, \sim q} \right)$ is equivalent to $p \leftrightarrow q$

Statement $-2$ : $ \sim \left( {p \leftrightarrow \, \sim q} \right)$ is a tautology.

A

Statement $-1$ is True, Statement $-2$ is True;
Statement $-2$ is a correct explanation for Statement $-1$ .

B

Statement $-1$ is True, Statement $-2$ is True;
Statement $-2$ is $NOT$ a correct explanation for Statement $-1$ .

C

Statement $-1$ is True, Statement $-2$ is False.

D

Statement $-1$ is False, Statement $-2$ is True.

Solution

Do yourself

Standard 11
Mathematics

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