Suppose that angular velocity of rotation of earth is increased. Then, as a consequence.

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7.Gravitation

medium

Suppose that the angular velocity of rotation of earth is increased. Then, as a consequence.

There will be no change in weight anywhere on the earth

Weight of the object, everywhere on the earth, wild decrease

Weight of the object, everywhere on the earth, will increase

Except at poles, weight of the object on the earth will decrease

(JEE MAIN-2018)

Solution

With rotation of earth or latitude, acceleration due to gravity vary as $g' = g – {\omega ^2}R\,\,{\cos ^2}\,\phi $ Where $\phi $ is latitude, there will be no change in gravity at poles as $\phi = 90^o$ At all other points as $\omega $ increases $g'$ will decreases hence, weight, $W = mg$ decreases.

Standard 11

Physics

If the radius of the earth shrinks by $1.5\%$ (mass remaining same), then the value of acceleration due to gravity changes by ……. $\%$.

easy

The acceleration due to gravity about the earth's surface would be half of its value on the surface of the earth at an altitude of ……… $mile$. ($R = 4000$ mile)

medium

A particle is dropped on Earth from height $R$ (radius of Earth) and it bounces back to a height $R/2$ the coefficient of restitution for collision is (ignore air resistance and rotation of Earth)

normal

The height of the point vertically above the earth’s surface, at which acceleration due to gravity becomes $1\%$ of its value at the surface is (Radius of the earth $= R$)

medium

In both figures shown below a hole along the diameter of earth. In first, a particle is released from $A$ and it oscillated with time period $T_1$. In second figure, same particle is released from point $B$ and it oscillates with time period $T_2$ then [$O$ is centre of earth]

hard

Suppose that the angular velocity of rotation of earth is increased. Then, as a consequence.

Solution

Similar Questions

If the radius of the earth shrinks by $1.5\%$ (mass remaining same), then the value of acceleration due to gravity changes by ……. $\%$.

The acceleration due to gravity about the earth's surface would be half of its value on the surface of the earth at an altitude of ……… $mile$. ($R = 4000$ mile)

A particle is dropped on Earth from height $R$ (radius of Earth) and it bounces back to a height $R/2$ the coefficient of restitution for collision is (ignore air resistance and rotation of Earth)

The height of the point vertically above the earth’s surface, at which acceleration due to gravity becomes $1\%$ of its value at the surface is (Radius of the earth $= R$)

In both figures shown below a hole along the diameter of earth. In first, a particle is released from $A$ and it oscillated with time period $T_1$. In second figure, same particle is released from point $B$ and it oscillates with time period $T_2$ then [$O$ is centre of earth]

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