Gujarati
7.Gravitation
medium

The acceleration due to gravity about the earth's surface would be half of its value on the surface of the earth at an altitude of ......... $mile$. ($R = 4000$ mile)

A

$1200$

B

$2000$

C

$1600$

D

$4000$

Solution

(c) $\frac{{g'}}{g} = {\left( {\frac{R}{{R + h}}} \right)^2}$ ==> $\frac{1}{2} = {\left( {\frac{R}{{R + h}}} \right)^2}$==>$\frac{1}{2} = {\left( {\frac{{4000}}{{4000 + h}}} \right)^2}$

By solving we get $\,\,h = 1656.85\,\,mile \approx 1600\,\,mile$

Standard 11
Physics

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