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10-2.Transmission of Heat
hard
Temperature difference of $120\,^oC$ is maintained between two ends of a uniform rod $AB$ of length $2L$. Another bent rod $PQ$, of same cross-section as $AB$ and length $\frac{{3L}}{2}$, is connected across $AB$ (See figure). In steady state, temperature difference between $P$ and $Q$ will be close to .......... $^oC$

A
$45$
B
$75$
C
$60$
D
$35$
(JEE MAIN-2019)
Solution

${T_A} – {T_B} = \frac{{{T_1} – {T_2}}}{{\frac{{8R}}{5}}} \times \frac{{3R}}{5} = \frac{3}{8} \times 120 = 45$
Standard 11
Physics
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