10-2.Transmission of Heat
hard

Temperature difference of $120\,^oC$ is maintained between two ends of a uniform rod $AB$ of length $2L$. Another bent rod $PQ$, of same cross-section as $AB$ and length $\frac{{3L}}{2}$,  is connected across $AB$ (See figure). In steady state, temperature difference between $P$ and $Q$ will be close to .......... $^oC$

A

$45$

B

$75$

C

$60$

D

$35$

(JEE MAIN-2019)

Solution

${T_A} – {T_B} = \frac{{{T_1} – {T_2}}}{{\frac{{8R}}{5}}} \times \frac{{3R}}{5} = \frac{3}{8} \times 120 = 45$

Standard 11
Physics

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