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4-1.Newton's Laws of Motion
easy
Ten one-rupeed coins are put on top of each other on a table. Each coin has mass $m$. The reaction of the $6^{th}$ coin (counted from the bottom) on the $7^{th}$ coins is .......... $mg$
A
$4$
B
$6 $
C
$7 $
D
$3 $
Solution
The sixth coin is under the weight of four coins above it. Hence, Reaction of the $6^{th}$ coin on the $7^{th}$ coin = Force on the $6^{th}$ coin due to $7^{th}$ coin $= 4\,mg$
Standard 11
Physics