Ten students are seated at random in a row. T | vedclass

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Question

(a) Total ways $ = 10\,\,!$

Two boys can sit side by side in $2 	imes 9\,\,!$ ways.

So probaibility $ = \frac{{2 	imes 9\,\,!}}{{10\,\,!}} = \

Vedclass · Accepted Answer

$\frac{4}{5}$

Vedclass · Answer

(a) Total ways $ = 10\,\,!$

Two boys can sit side by side in $2 	imes 9\,\,!$ ways.

So probaibility $ = \frac{{2 	imes 9\,\,!}}{{10\,\,!}} = \frac{1}{5}$

Thus the probability that they are not seated together is $1 - \frac{1}{5} = \frac{4}{5}.$

Ten students are seated at random in a row. The probability that two particular students are not seated side by side is

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