A bag contains 6 red, 5 white and 4 black balls. Two balls are drawn. probability that none of them

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14.Probability

easy

A bag contains $6$ red, $5$ white and $4$ black balls. Two balls are drawn. The probability that none of them is red, is

A

$\frac{{12}}{{35}}$

B

$\frac{6}{{35}}$

C

$\frac{4}{{35}}$

D

None of these

Solution

(a) Required probability $ = \frac{{{}^9{C_2}}}{{{}^{15}{C_2}}} = \frac{{9 \times 8}}{{15 \times 14}} = \frac{{12}}{{35}}.$

Standard 11

Mathematics

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