- Home
- Standard 11
- Mathematics
14.Probability
easy
In a lottery there were $90$ tickets numbered $1$ to $90$. Five tickets were drawn at random. The probability that two of the tickets drawn numbers $15$ and $89$ is
A
$\frac{2}{{801}}$
B
$\frac{2}{{623}}$
C
$\frac{1}{{267}}$
D
$\frac{1}{{623}}$
Solution
(a) Required probability $ = \frac{{^{88}{C_3}}}{{^{90}{C_5}}} = \frac{2}{{801}}$.
Standard 11
Mathematics