Gujarati
14.Probability
easy

In a lottery there were $90$ tickets numbered $1$ to $90$. Five tickets were drawn at random. The probability that two of the tickets drawn numbers $15$ and $89$ is

A

$\frac{2}{{801}}$

B

$\frac{2}{{623}}$

C

$\frac{1}{{267}}$

D

$\frac{1}{{623}}$

Solution

(a) Required probability $ = \frac{{^{88}{C_3}}}{{^{90}{C_5}}} = \frac{2}{{801}}$.

Standard 11
Mathematics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.