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6-2.Equilibrium-II (Ionic Equilibrium)
medium
$20\%$ आयनित डेसीनॉर्मल $N{H_4}OH$ विलयन का $pH$ मान होगा
A
$13.3$
B
$14.7$
C
$12.3$
D
$12.95$
(AIPMT-1998)
Solution
(c) $N{H_4}OH$ के लिए
$[O{H^ – }] = C\,.\,\alpha $ ; $C = \frac{1}{{10}}M$, $\alpha = 0.2$
$[O{H^ – }] = \frac{1}{{10}} \times 0.2 = 2 \times {10^{ – 2}}\,M$
$pOH = – \log \,\,[O{H^ – }]$$ = \log \,\,[2 \times {10^{ – 2}}]$; $pOH = 1.7$
$pH = 14 – pOH$ $ = 14 – 1.7 = 12.30$.
Standard 11
Chemistry
