The pH value of decinormal solution of N{H_4} | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(c) For $N{H_4}OH$.

$[O{H^ - }] = C\,.\,\alpha $ ; $C = \frac{1}{{10}}M$, $\alpha = 0.2$

$[O{H^ - }] = \frac{1}{{10}} 	imes 0.2 = 2 	imes {10^

Vedclass · Accepted Answer

$12.3$

Vedclass · Answer

(c) For $N{H_4}OH$.

$[O{H^ - }] = C\,.\,\alpha $ ; $C = \frac{1}{{10}}M$, $\alpha = 0.2$

$[O{H^ - }] = \frac{1}{{10}} 	imes 0.2 = 2 	imes {10^{ - 2}}\,M$

$pOH = - \log \,\,[O{H^ - }]$$ = \log \,\,[2 	imes {10^{ - 2}}]$; $pOH = 1.7$

$pH = 14 - pOH$ $ = 14 - 1.7 = 12.30$.

The $pH$ value of decinormal solution of $N{H_4}OH$ which is $20\%$ ionised, is

Similar Questions

$HClO$ is a weak acid. The concentration of ${H^ + }$ ions in $0.1\,M$ solution of $HClO\,({K_a} = 5 \times {10^{ - 8}})$ will be equal to

Explain a general step-wise approach to evaluate the $pH$ of the weak electrolyte.

Which oxychloride has maximum $pH$

Sulphurous acid $\left( H _{2} SO _{3}\right)$ has $Ka _{1}=1.7 \times 10^{-2}$ and $Ka _{2}=6.4 \times 10^{-8} .$ The $pH$ of $0.588 \,M\, H _{2} SO _{3}$ is ..... . (Round off to the Nearest Integer)

The ${K_b}$ of ammonia is $1.8 \times {10^{ - 5}}$ at $298$ $K$ temperature. Calculate the $pH$ of $0.1$ $M$ solution.