PH of a 0.01,M solution of acetic acid having degree of dissociation 12.5% is

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6-2.Equilibrium-II (Ionic Equilibrium)

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The $pH $ of a $0.01\,M$ solution of acetic acid having degree of dissociation $12.5\%$ is

A

$5.623$

B

$2.903$

C

$3.723$

D

$4.509$

Solution

(b) $[{H^ + }] = C\alpha = 0.01 \times \frac{{1.25}}{{100}}$

${H^ + } = 1.25 \times {10^{ – 3}}$; $pH = {\text{between}}\,\,\,{\text{2}}\,\,{\text{or}}\,\,{\text{3}} = {\text{2}}{\text{.90}}$

Standard 11

Chemistry

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