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7.Gravitation
easy
The acceleration due to gravity on the planet $ A $ is $9$ times the acceleration due to gravity on planet $B$. $A$ man jumps to a height of $2\,m$ on the surface of $ A$. What is the height of jump by the same person on the planet $B$..........$m$
A
$18$
B
$6$
C
$\frac{2}{3}$
D
$\frac{2}{9}$
(AIPMT-2003)
Solution
(a) ${H_{\max }} = \frac{{{u^2}}}{{2g}} \Rightarrow {H_{\max }} \propto \frac{1}{g}$
On planet $B$ value of $g$ is $1/9$ times to that of $A$. So value of ${H_{\max }}$ will become $9$ times i.e.$2 \times 9 = 18\;metre$
Standard 11
Physics
