The accompanying graph of position $x$ versus time $t$ represents the motion of a particle. If $p$ and $q$ are both positive constants, the expression that best describes the acceleration $a$ of the particle is
$a=-p-q t$
$a=-p+q t$
$a=p+q t$
$a=p-q t$
A particle moves in a straight line and its position $x$ at time $t$ is given by $x^2=2+t$. Its acceleration is given by
The velocity time graph of a body is shown in Figure. It implies that at point $B$ :-
A particle moves towards east with velocity $5\, m/s$. After $10$ seconds its direction changes towards north with same velocity. The average acceleration of the particle is
The velocity $(v)$ of a particle moving along $x$-axis varies with its position $x$ as shown in figure. The acceleration $(a)$ of particle varies with position $(x)$ as
When acceleration and average acceleration are equal for moving object ?