Gujarati
2.Motion in Straight Line
normal

The accompanying graph of position $x$ versus time $t$ represents the motion of a particle. If $p$ and $q$ are both positive constants, the expression that best describes the acceleration $a$ of the particle is

A

$a=-p-q t$

B

$a=-p+q t$

C

$a=p+q t$

D

$a=p-q t$

(KVPY-2013)

Solution

(d)

We have following observations from position $x$ versus time $t$ graph.

From above graph we can draw following velocity $v$ versus time $t$ graph.

So, acceleration of given particle is initially positive but with time it becomes negative.

Hence, $a=p-q t$ is best suited option.

Standard 11
Physics

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