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2.Motion in Straight Line
normal
The accompanying graph of position $x$ versus time $t$ represents the motion of a particle. If $p$ and $q$ are both positive constants, the expression that best describes the acceleration $a$ of the particle is

A
$a=-p-q t$
B
$a=-p+q t$
C
$a=p+q t$
D
$a=p-q t$
(KVPY-2013)
Solution

(d)
We have following observations from position $x$ versus time $t$ graph.
From above graph we can draw following velocity $v$ versus time $t$ graph.
So, acceleration of given particle is initially positive but with time it becomes negative.
Hence, $a=p-q t$ is best suited option.
Standard 11
Physics