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8.Mechanical Properties of Solids
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The adjacent graph shows the extension $(\Delta l)$ of a wire of length $1\, m$ suspended from the top of a roof at one end and with a load $W$ connected to the other end. If the cross-sectional area of the wire is $10^{-6}\, m^2$, calculate the Young’s modulus of the material of the wire.
A
$2\times10^{11}\, N/m^2$
B
$2\times10^{-11}\, N/m^2$
C
$3\times10^{-12}\, N/m^2$
D
$2\times10^{-13}\, N/m^2$
(AIIMS-2008)
Solution
$Y = \frac{F}{A}/\frac{{\Delta l}}{l} = \frac{{20 \times 1}}{{{{10}^{ – 6}} \times {{10}^{ – 4}}}}$
$ = 2 \times {10^{11}}N/{m^2}$
Standard 11
Physics
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