The stress-strain graphs for materials $A$ and $B$ are shown in Figure
The graphs are drawn to the same scale.
$(a)$ Which of the materials has the greater Young’s modulus?
$(b)$ Which of the two is the stronger material?
(a) A ; (b) A
For a given strain, the stress for material $A$ is more than it is for material $B ,$ as shown in the two graphs.
Young's modulus $=\frac{\text { stress }}{\text { strain }}$
For a given strain, if the stress for a material is more, then Young's modulus is also greater for that material. Therefore, Young's modulus for material $A$ is greater than it is for material $B.$
The amount of stress required for fracturing a material, corresponding to its fracture point, gives the strength of that material. Fracture point is the extreme point in a stress-strain curve. It can be observed that material $A$ can withstand more strain than material $B$.
Hence, material $A$ is stronger than material $B$.
In the below graph, point $B$ indicates
The load versus strain graph for four wires of the same material is shown in the figure. The thickest wire is represented by the line
The stress versus strain graphs for wires of two materials $A$ and $B$ are as shown in the figure. If $Y_A$ and $Y_B$ are the Young's modulus of the materials, then
In the below graph, point $D$ indicates
A student plots a graph from his reading on the determination of Young’s modulus of a metal wire but forgets to label. The quantities on $X$ and $Y$ axes may be respectively.