Gujarati
Hindi
1. Electric Charges and Fields
normal

The adjoining diagram shows the electric lines of force emerging from a charged body. If the electric fields at $A$ and $B$ are $E_A$ and $E_B$ respectively and the distance between them is $r$, then

A

$E_A > E_B$

B

$E_A < E_B$

C

$E_A = E_B$

D

${E_A} > \frac{{{E_B}}}{{{r^2}}}$

Solution

Electric field at a point is numerically equal to the number of lines of force crossing normally per unit area surrounding that point. Thus electric field at $A$ is stronger than at $B$.

Standard 12
Physics

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