1.Units, Dimensions and Measurement
medium

The amount of heat energy $Q$, used to heat up a substance depends on its mass $m$, its specific heat capacity $(s)$ and the change in temperature $\Delta T$ of the substance. Using dimensional method, find the expression for $s$ is (Given that $\left.[s]=\left[ L ^2 T ^{-2} K ^{-1}\right]\right)$ is

A

$Q m \Delta T$

B

$\frac{Q}{m \Delta T}$

C

$\frac{Q m}{\Delta T}$

D

$\frac{m}{Q \Delta T}$

Solution

(b)

$Q=m^a s^b \theta^c$

$\left[ ML ^2 T ^{-2}\right]=\left[ M ^2\right]\left[ L ^{2 b} T ^{-2 b} K ^{-b}\right]\left[ K ^{ C }\right]$

$\Rightarrow a=1$,

$2 b=2 \Rightarrow b=1$

$-b+c=0$

$\Rightarrow b=c \Rightarrow c=1$

$Q=m s \Delta T$

$\Rightarrow s=\frac{Q}{m \Delta T}$

Standard 11
Physics

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