8.Electromagnetic waves
medium

निर्वात में एक आवर्त वैध्यूतचुंबकीय तरंग के चुंबकीय क्षेत्र वाले भाग का आयाम $B_{0}=510 nT$ है। तरंग के विध्यूत क्षेत्र वाले भाग का आयाम क्या है?

A

$205$

B

$114$

C

$186$

D

$153$

Solution

Amplitude of magnetic field of an electromagnetic wave in a vacuum,

$B_{0}=510 nT =510 \times 10^{-9} T$

Speed of light in a vacuum, $c=3 \times 10^{8} m / s$

Amplitude of electric field of the electromagnetic wave is given by the relation,

$E=c B_{0}=3 \times 10^{8} \times 510 \times 10^{-9}=153 N / C$

Therefore, the electric field part of the wave is $153 N / C$.

Standard 12
Physics

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