8.Electromagnetic waves
medium

The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is $B_0 = 510 \;nT$.What is the amplitude of the electric field (in $N/C$) part of the wave?

A

$205$

B

$114$

C

$186$

D

$153$

Solution

Amplitude of magnetic field of an electromagnetic wave in a vacuum,

$B_{0}=510 nT =510 \times 10^{-9} T$

Speed of light in a vacuum, $c=3 \times 10^{8} m / s$

Amplitude of electric field of the electromagnetic wave is given by the relation,

$E=c B_{0}=3 \times 10^{8} \times 510 \times 10^{-9}=153 N / C$

Therefore, the electric field part of the wave is $153 N / C$.

Standard 12
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.