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8.Electromagnetic waves
medium
The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is $B_0 = 510 \;nT$.What is the amplitude of the electric field (in $N/C$) part of the wave?
A
$205$
B
$114$
C
$186$
D
$153$
Solution
Amplitude of magnetic field of an electromagnetic wave in a vacuum,
$B_{0}=510 nT =510 \times 10^{-9} T$
Speed of light in a vacuum, $c=3 \times 10^{8} m / s$
Amplitude of electric field of the electromagnetic wave is given by the relation,
$E=c B_{0}=3 \times 10^{8} \times 510 \times 10^{-9}=153 N / C$
Therefore, the electric field part of the wave is $153 N / C$.
Standard 12
Physics