Gujarati
8.Electromagnetic waves
easy

$TV$ तरंगों के तरंगदैध्र्य का क्रम $1-10\, meter $ है तो इसकी आवृत्ति का क्रम $MHz$ में होगा

A

$30-300$

B

$3-30$

C

$300-3000$

D

$3-3000$

Solution

(a)$v = \frac{C}{\lambda } \Rightarrow {v_1} = \frac{{3 \times {{10}^8}}}{1}$ = $3 \times {10^8}Hz = 300\;MHz$
एवं ${v_2} = \frac{{3 \times {{10}^8}}}{{10}}$=$3 \times {10^7}Hz = 30MHz$

Standard 12
Physics

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