Two particles A and B are moving in horizontal plane as shown in figure at t = 0 , then time after w

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3-2.Motion in Plane

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Two particles $A$ and $B$ are moving in horizontal plane as shown in figure at $t = 0$ , then time after which $A$ will catch $B$ will be.......$s$

A

$4$

B

$5$

C

$2$

D

$8$

Solution

To catch $\left(\mathrm{v}_{\mathrm{y}}\right)_{\mathrm{A}}=\left(\mathrm{v}_{\mathrm{y}}\right)_{\mathrm{B}}$

$\Rightarrow v \sin 37^{\circ}=30$

$\Rightarrow \mathrm{v}=\frac{30}{3 / 5}=50 \mathrm{m} / \mathrm{s}$

Time taken $=\frac{200}{v \cos 37^{\circ}}=5 \mathrm{s}$

Standard 11

Physics

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