Two wires of the same material have lengths in the ratio 1 : 2 and their radii are in the ratio $1:\sqrt 2 $. If they are stretched by applying equal forces, the increase in their lengths will be in the ratio

If the length of a wire is made double and radius is halved of its respective values. Then, the Young's modules of the material of the wire will :

A rubber pipe of density $1.5 \times {10^3}\,N/{m^2}$ and Young's modulus $5 \times {10^6}\,N/{m^2}$ is suspended from the roof. The length of the pipe is $8 \,m$. What will be the change in length due to its own weight

The force required to stretch a steel wire of $1\,c{m^2}$ cross-section to $1.1$ times its length would be $(Y = 2 \times {10^{11}}\,N{m^{ – 2}})$

The temperature of a wire of length $1$ metre and area of cross-section $1\,c{m^2}$ is increased from $0°C$ to $100°C$. If the rod is not allowed to increase in length, the force required will be $(\alpha = {10^{ – 5}}/^\circ C$ and $Y = {10^{11}}\,N/{m^2})$