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8.Mechanical Properties of Solids
medium
A rubber pipe of density $1.5 \times {10^3}\,N/{m^2}$ and Young's modulus $5 \times {10^6}\,N/{m^2}$ is suspended from the roof. The length of the pipe is $8 \,m$. What will be the change in length due to its own weight
A
$9.6\, m$
B
$9.6 \times {10^3}\,m$
C
$19.2 \times {10^{ - 2}}\,m$
D
$9.6 \times {10^{ - 2}}\,m$
Solution
(d) $l = \frac{{{L^2}dg}}{{2Y}}$$ = \frac{{{{(8)}^2} \times 1.5 \times {{10}^3} \times 10}}{{2 \times 5 \times {{10}^6}}} = 9.6 \times {10^{ – 2}}m$
Standard 11
Physics
