Area of each plate of a parallel plate capacitor is 100,c{m^2} and distance between plates is 1,mm .

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2. Electric Potential and Capacitance

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The area of each plate of a parallel plate capacitor is $100\,c{m^2}$and the distance between the plates is $1\,mm$. It is filled with mica of dielectric $6$. The radius of the equivalent capacity of the sphere will be.......$m$

A

$47.7$

B

$4.77$

C

$477$

D

None of the above

Solution

(b) $C = \frac{{{\varepsilon _0}AK}}{d} = 4\pi {\varepsilon _0}r$
$r$ = Radius of sphere of equivalent capacity
$==>$ $r = \frac{{AK}}{{4\pi d}} = \frac{{100 \times {{10}^{ – 4}} \times 6}}{{1 \times {{10}^{ – 3}} \times 4 \times 3.14}}$$ = \frac{{15}}{{3.14}} = 4.77\,m$

Standard 12

Physics

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