A capacitor has capacitance 5 μ F when it's parallel plates are separated by air medium of thic

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2. Electric Potential and Capacitance

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A capacitor has capacitance $5 \mu F$ when it's parallel plates are separated by air medium of thickness $d$. A slab of material of dielectric constant $1.5$ having area equal to that of plates but thickness $\frac{ d }{2}$ is inserted between the plates. Capacitance of the capacitor in the presence of slab will be $..........\mu F$

A

$5$

B

$6$

C

$4$

D

$3$

(JEE MAIN-2023)

Solution

$C _{\text {new }}=\frac{\in_0 A }{\frac{\left(\frac{ d }{2}\right)}{1.5}+\frac{\left(\frac{ d }{2}\right)}{1}}$

$=\frac{\in_0 A}{\left(\frac{d}{3}+\frac{d}{2}\right)}=\frac{6 \in_0 A}{5 d}$

$=\frac{6}{5} \times 5 \mu F =6 \mu F$

Standard 12

Physics

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