The area of the parallelogram determined by $A =2 \hat{ i }+\hat{ j }-3 \hat{ k }$ and $B =12 \hat{ j }-2 \hat{ k }$ is approximately
- A$43$
- B$56$
- C$38$
- D$74$
Similar Questions
Obtain scalar product in terms of Cartesian component of vectors.
Obtain scalar product in terms of Cartesian component of vectors.
Vector $P =6 \hat{ i }+4 \sqrt{2} \hat{ j }+4 \sqrt{2} \hat{ k }$ makes angle from $z$-axis equal to
The angle between the two vectors $\overrightarrow A = 5\hat i + 5\hat j$ and $\overrightarrow B = 5\hat i - 5\hat j$ will be ....... $^o$
The angle between the two vectors $\overrightarrow A = 5\hat i + 5\hat j$ and $\overrightarrow B = 5\hat i - 5\hat j$ will be ....... $^o$
If $\overrightarrow A \times \overrightarrow B=\overrightarrow B \times \overrightarrow A$ then the angle between $\overrightarrow A$ and $\overrightarrow B$ is
If $\overrightarrow A \times \overrightarrow B=\overrightarrow B \times \overrightarrow A$ then the angle between $\overrightarrow A$ and $\overrightarrow B$ is
- [AIEEE 2004]