The bond order and magnetic behaviour of math | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$\mathrm{O}_{2}^{-}=\left(\sigma_{1 \mathrm{~s}}\right)^{2}\left(\sigma_{1 \mathrm{~s}}^{*}\right)^{2}\left(\sigma_{2 \mathrm{~s}}\right)^{2}\left(\si

Vedclass · Accepted Answer

$1.5$ and paramagnetic

Vedclass · Answer

$\mathrm{O}_{2}^{-}=\left(\sigma_{1 \mathrm{~s}}ight)^{2}\left(\sigma_{1 \mathrm{~s}}^{*}ight)^{2}\left(\sigma_{2 \mathrm{~s}}ight)^{2}\left(\sigma_{2 \mathrm{~s}}^{*}ight)^{2}\left(\sigma_{2 \mathrm{p}_{\mathrm{z}}}ight)^{2}$

$\left(\pi_{2 \mathrm{p}_{\mathrm{x}}}^{2}=\pi_{2 \mathrm{p}_{\mathrm{y}}}^{2}ight)\left(\pi_{2 \mathrm{p}_{\mathrm{x}}}^{*_{2}}=\pi_{2 \mathrm{p}_{\mathrm{y}}}^{*_{1}}ight)$

$	ext { Bond order }=\frac{10-7}{2}=1.5$

and paramagnetic

The bond order and magnetic behaviour of $\mathrm{O}_{2}^{-}$ion are, respectively:

Similar Questions

The molecular electronic configuration of $H_2^ - $ ion is

Give electron configuration, bond order, Magnetic property and energy diagram for Baron $\left( {{{\rm{B}}_2}} \right)$ Molecule and write about it existence.

The paramagnetic property of the oxygen molecule due to the presence of unpaired electorns present in

Incorrect statement when $C_2$ change to $C_2^{-2}$

Use molecular orbital theory to explain why the $Be_{2}$ molecule does not exist.