Bond order of NO molecule is

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4.Chemical Bonding and Molecular Structure

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The bond order of $NO$ molecule is

$1$

$2$

$2.5$

$3$

Solution

(c) ${\rm{B}}{\rm{.O}}{\rm{.}} = \frac{{{\rm{No}}{\rm{. of bonding }}{e^ – } – {\rm{ No}}{\rm{. of antibonding }}{e^ – }}}{2}$ $ = \frac{{8 – 3}}{2} = \frac{5}{2} = 2.5$.

Standard 11

Chemistry

In the conversion of $N_2$ into $N_2^+$ the electron will be lost from which of the following molecular orbital ?

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$AX$ is a covalent diatomic molecule where $A$ and $X$ are second row elements of periodic table. Based on Molecular orbital theory, the bond order of $AX$ is $2.5$. The total number of electrons in $AX$ is ……….. (Round off to the Nearest Integer).

medium

(JEE MAIN-2021)

$O_2^{2 – }$is the symbol of .. ion

easy

The number of antibonding electron pairs in $O_2^{2 – }$ molecular ion on the basis of molecular orbital theory is

hard

Identify a molecule which does not exist.

medium

(NEET-2020)

The bond order of $NO$ molecule is

Solution

Similar Questions

In the conversion of $N_2$ into $N_2^+$ the electron will be lost from which of the following molecular orbital ?

$AX$ is a covalent diatomic molecule where $A$ and $X$ are second row elements of periodic table. Based on Molecular orbital theory, the bond order of $AX$ is $2.5$. The total number of electrons in $AX$ is ……….. (Round off to the Nearest Integer).

$O_2^{2 – }$is the symbol of .. ion

The number of antibonding electron pairs in $O_2^{2 – }$ molecular ion on the basis of molecular orbital theory is

Identify a molecule which does not exist.

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