Gujarati
4.Chemical Bonding and Molecular Structure
medium

$NO$ अणु की बन्ध कोटि है   

A

$1$

B

$2$

C

$2.5$

D

$3$

Solution

बन्ध क्रम

${\text{B}}{\text{.O}}{\text{.}} = \frac{{{\text{No}}{\text{. of bonding }}{e^ – } – {\text{ No}}{\text{. of antibonding }}{e^ – }}}{2}$

 $ = \frac{{8 – 3}}{2} = \frac{5}{2} = 2.5$

Standard 11
Chemistry

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