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4.Chemical Bonding and Molecular Structure
medium
$NO$ अणु की बन्ध कोटि है
A
$1$
B
$2$
C
$2.5$
D
$3$
Solution
बन्ध क्रम
${\text{B}}{\text{.O}}{\text{.}} = \frac{{{\text{No}}{\text{. of bonding }}{e^ – } – {\text{ No}}{\text{. of antibonding }}{e^ – }}}{2}$
$ = \frac{{8 – 3}}{2} = \frac{5}{2} = 2.5$
Standard 11
Chemistry