The capacitance of a parallel plate capacitor is $12\,\mu \,F$. If the distance between the plates is doubled and area is halved, then new capacitance will be.........$\mu \,F$
The capacitance of a parallel plate capacitor is $12\,\mu \,F$. If the distance between the plates is doubled and area is halved, then new capacitance will be.........$\mu \,F$
- A
$8$
- B
$6$
- C
$4$
- D
$3$
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