The charge given to any conductor resides on its outer surface, because
The charge given to any conductor resides on its outer surface, because
- A
The free charge tends to be in its minimum potential energy state
- B
The free charge tends to be in its minimum kinetic energy state
- C
The free charge tends to be in its maximum potential energy state
- D
The free charge tends to be in its maximum kinetic energy state
Similar Questions
Four charges are arranged at the corners of a square $ABCD$ of side $d$, as shown in Figure
$(a)$ Find the work required to put together this arrangement.
$(b)$ A charge $q_{0}$ is brought to the centre $E$ of the square, the four charges being held fixed at its corners. How much extra work is needed to do this?
Four charges are arranged at the corners of a square $ABCD$ of side $d$, as shown in Figure
$(a)$ Find the work required to put together this arrangement.
$(b)$ A charge $q_{0}$ is brought to the centre $E$ of the square, the four charges being held fixed at its corners. How much extra work is needed to do this?
When a proton is accelerated through $1\,V$, then its kinetic energy will be.....$eV$
When a proton is accelerated through $1\,V$, then its kinetic energy will be.....$eV$
- [AIPMT 1999]
A proton is about $1840$ times heavier than an electron. When it is accelerated by a potential difference of $1\, kV$, its kinetic energy will be......$keV$
A proton is about $1840$ times heavier than an electron. When it is accelerated by a potential difference of $1\, kV$, its kinetic energy will be......$keV$
- [AIIMS 2003]
Positive and negative point charges of equal magnitude are kept at $\left(0,0, \frac{a}{2}\right)$ and $\left(0,0, \frac{-a}{2}\right)$, respectively. The work done by the electric field when another positive point charge is moved from $(-a, 0,0)$ to $(0, a, 0)$ is
Positive and negative point charges of equal magnitude are kept at $\left(0,0, \frac{a}{2}\right)$ and $\left(0,0, \frac{-a}{2}\right)$, respectively. The work done by the electric field when another positive point charge is moved from $(-a, 0,0)$ to $(0, a, 0)$ is
- [IIT 2007]
There is a uniform spherically symmetric surface charge density at a distance $R_0$ from the origin. The charge distribution is initially at rest and starts expanding because of mutual repulsion. The figure that represents best the speed $V(R(t))$ of the distribution as a function of its instantaneous radius $R(t)$ is
There is a uniform spherically symmetric surface charge density at a distance $R_0$ from the origin. The charge distribution is initially at rest and starts expanding because of mutual repulsion. The figure that represents best the speed $V(R(t))$ of the distribution as a function of its instantaneous radius $R(t)$ is
- [JEE MAIN 2019]