- Home
- Standard 11
- Mathematics
10-1.Circle and System of Circles
hard
The circles ${x^2} + {y^2} = 9$ and ${x^2} + {y^2} - 12y + 27 = 0$ touch each other. The equation of their common tangent is
A
$4y = 9$
B
$y = 3$
C
$y = - 3$
D
$x = 3$
Solution
(b) ${S_1} = {x^2} + {y^2} – 12y + 27 = 0$
${S_2} = {x^2} + {y^2} – 9 = 0$
The equation of common tangent is
${S_1} – {S_2} = 0 $
$\Rightarrow – 12y + 36 = 0$
$\Rightarrow y = 3$.
Standard 11
Mathematics