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3-2.Motion in Plane
normal
The co-ordinates of a moving particle at a time $t$, are give by, $x = 5 sin 10 t, y = 5 cos 10t$. The speed of the particle is :
A
$25$
B
$50$
C
$10$
D
None
Solution
$v_{x}=\frac{d x}{d t}=50 \cos 10 t$
$v_{y}=\frac{d y}{d t}=-50 \sin 10 t$
Speed $=\sqrt{v_{x}^{2}+v_{y}^{2}}$
$=\sqrt{(50 \cos 10 t)^{2}+(-50 \sin 10 t)^{2}}=50$
Standard 11
Physics