A particle P is moving in a circle of radius 'a' with a uniform speed v . C is centre of cir

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3-2.Motion in Plane

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A particle $P$ is moving in a circle of radius $'a'$ with a uniform speed $v$ . $C$ is the centre of the circle and $AB$ is a diameter. When passing through $B$ the angular velocity of $P$ about $A$ and $C$ are in the ratio

A$1 : 1$

B$1 : 2$

C$2 : 1$

D$4 : 1$

Solution

$\frac{\omega_{A}}{\omega_{C}}=\frac{\frac{V_{A}}{r_{A}}}{\frac{V_{C}}{r_{C}}}=\frac{r_{C}}{r_{A}}$
$=\frac{a}{2 a}=\frac{1}{2}$

Standard 11

Physics

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