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9.Straight Line
normal
The co-ordinates of three points $A(-4, 0) ; B(2, 1)$ and $C(3, 1)$ determine the vertices of an equilateral trapezium $ABCD$ . The co-ordinates of the vertex $D$ are :
A
$(6, 0)$
B
$(- 3, 0)$
C
$(- 5, 0)$
D
$(9, 0)$
Solution
Equilateral mean isosceles trapezium
Standard 11
Mathematics