9.Straight Line
normal

The co-ordinates of three points $A(-4, 0) ; B(2, 1)$ and $C(3, 1)$ determine the vertices of an equilateral trapezium $ABCD$ . The co-ordinates of the vertex $D$ are :

A

$(6, 0)$

B

$(- 3, 0)$

C

$(- 5, 0)$

D

$(9, 0)$

Solution

Equilateral mean isosceles trapezium 

Standard 11
Mathematics

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